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Results 31 to 45 of 93
Thread: Maths problem 9999
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7th March 2008, 09:19 AM #31
Sorry Greg, there were too many (((((( and I read it wrong. 20 works now.
My bad.
Well done
Visit my website at www.myFineWoodWork.com
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7th March 2008, 09:22 AM #32
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14, 16 and 20
Still want to see your method Wongo, to see what you do here.
Thanks
Greg
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7th March 2008, 09:26 AM #33
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7th March 2008, 04:16 PM #34
You've got to risk it to get the biscuit
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good work wongy, greg and russel
S T I R L O
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7th March 2008, 06:54 PM #35
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7th March 2008, 10:32 PM #36
n! = n * n-1 * n-2 * n-3 * ....* 1
for example
4! = 4 * 3 * 2 * 1
1! = 1
By definition 0! = 1
9 + (square root 9)! + 9/9
= 9 + 3! + 9/9
= 9 + 6 + 1
=16Visit my website at www.myFineWoodWork.com
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8th March 2008, 12:20 PM #37
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Interesting. I can do 21 and 22, can you?
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8th March 2008, 10:02 PM #38
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No takers? Actually, once you have got the idea it becomes almost mundane up to 64. 65 is a bit challenging and now I am stuck at 67. Think I will go back to woodworking. Anybody out there more determined than I am?
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8th March 2008, 10:24 PM #39
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9th March 2008, 11:56 AM #40
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9th March 2008, 10:21 PM #41
You've got to risk it to get the biscuit
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9th March 2008, 10:34 PM #42
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10th March 2008, 09:49 AM #43Visit my website at www.myFineWoodWork.com
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10th March 2008, 11:58 AM #44
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Thanks Wongo, once worked out that each 9 can be modified by symbols to make 1, 3, 6 and 9 I thought that maybe all integers could be made up with these four numbers, or something silly like that, but it appears that this hypothesis was too far fetched.
So, again, back to woodworking!
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10th March 2008, 04:25 PM #45
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