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Results 16 to 30 of 93
Thread: Maths problem 9999
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6th March 2008, 03:16 PM #16
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6th March 2008, 03:18 PM #17
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6th March 2008, 03:24 PM #18
You've got to risk it to get the biscuit
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6th March 2008, 03:27 PM #19
9 + (9 + 9 ) / 9 = 11
9 + (18) / 9
9 + 2 = 11
What is rule #1 in Arithmetic?
Oh dear...Visit my website at www.myFineWoodWork.com
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6th March 2008, 03:29 PM #20
You've got to risk it to get the biscuit
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6th March 2008, 04:20 PM #21
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dress to the nines
A late start but.....
9 + 9/9 + Square root of 9 = 13
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6th March 2008, 04:32 PM #22
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6th March 2008, 08:33 PM #23
( 9 + 6 ) - 9/9 = 14
( 9 + 6 ) + 9/9 = 16
( 9 + 9 ) + ( 6/sqrt9 ) = 20
you sod wongo I was trying to do my tax today this was the last thing I needed , had to take one of the grandsons for a walk after tea to look at it from out of the box , I take it upside down 9's are okAshore
The trouble with life is there's no background music.
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6th March 2008, 08:54 PM #24
You've got to risk it to get the biscuit
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hey wongy
is this allowed 14 = 99/9 +sqrt9 ??????????????
there's four ninesS T I R L O
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6th March 2008, 09:01 PM #25
If upside down 9's arn't then that is
Good one Stirlo
as would be 99/9 + 9 = 20
still leaves 16 thoughAshore
The trouble with life is there's no background music.
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7th March 2008, 07:24 AM #26
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20
If 99 isn't allowed:
(((Square root 9)! x 9) + (Square root 9)!)/Square root 9 = 20
greg
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7th March 2008, 07:33 AM #27
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16
9 + (square root 9)! + 9/9 = 16
greg
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7th March 2008, 09:04 AM #28
Sorry children
No 99, no 6. Just 9.
Greg, I like your approach.It is different from my way but I like it. You got game mate. 16 works but not 20.
2 left...
14
20Visit my website at www.myFineWoodWork.com
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7th March 2008, 09:11 AM #29
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20
let's see.
(square root9)! = 6
6 x 9 =54
54 + (square root 9)! = 60
60/ (Square root 9) = 20
Why doesn't this work?
Greg
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7th March 2008, 09:13 AM #30
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14
9 + (Square root 9)! - 9/9 = 14
Now Wongo..... I've showed you mine, you've got to show yours.....
Greg
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