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  1. #1
    Join Date
    Oct 2007
    Location
    Melbourne
    Age
    51
    Posts
    3

    Default Handrail timber for Kids fort

    I'm building a multilevel kids fort in the backyard.
    It's a construct and design.
    (you start building and design as you go)

    Handrails, I have the horizontals 140*45 (overkill but it fits better)
    But I'm unsure what timber to use for the verticals??

    I envisiged a square timber but would a dowel be better??

    I don't want to pay through the nose but I'm not cheapskate either??

    Help??

    KRS

  2. #2
    Join Date
    Sep 2007
    Location
    Canberra
    Posts
    154

    Default

    gday ksr
    it depends on what the uprights will do - is it to stop the kids getting through the gap, acting as a baluster? is it to support the handrail itself? both?

    how far is the handrail spanning between supports? is the handrail to protect against a drop, if yes then you would need some kind of restraint against outward pushing forces as well as merely supporting it vertically; do you want the uprights to contribute to this support as well?

    regards brynk

  3. #3
    Join Date
    Oct 2007
    Location
    Melbourne
    Age
    51
    Posts
    3

    Default

    Yes its to stop the kids from going through.
    Also is fall protection, deck heights are 500, 1000 and 1500

    I am only spanning 1500 with handrails so its not needed for support
    Top and bottom rails are 140*45 vertical bolted to posts, slightly overkill
    Height will be 1000 so vertical span will be 860-900

    I'm after (I think) a square (TP?) thats fairly small and won't bow too much

    Total lineal m is approx 9m so I'm hoping not too expensive as this fort has already set me back $1400 and still to add monkey bars,swings and of course a firemans pole.

    KRS

  4. #4
    Join Date
    Sep 2007
    Location
    Canberra
    Posts
    154

    Default

    gday ksr

    if you went for a round option, drilled 40mm into the top & bottom rails at 150 centres...
    1500/150 = 11, x 3 levels = 33 lengths at 1000 - 100 (top) - 100 (bottom) = 800; or about 27 metres overall

    i notice you mention total of 9 l.m's so im guessing your handrails are 2x 1500 long, therefore 27 becomes 54. this option may be priced competetively with the square members being fixed, would require less cost in terms of fixings but probably more time doing the fixing.

    food for thought, r's brynk

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