Woodworking Quiz;

[Ralph Jones]

Greetings Friends,

We are going to construct a gazebo with 8 sides and the inscribed diameter is 12 feet. How wide are each of the sides?

Respectfully, :)

[zymurgy]

Round to 1 decimal, 4.6'

Gordon.

[multinut]

if my calculations are correct
1 inch = 25.4mm
1 foot = 304.8mm
12 foot = 3657.6mm
this is the diametre of the gazebo
utilising pythagoras theorum and drawing many triangles i came up with a wall length of 1399.7mm
now the big problem of converting back into feet
4 foot 7 inch + 2.7mm
not sure how to break this into 8ths,16ths,32ths,or even 64ths

cheers
multinut
http://www.ubeaut.biz/crowd.gif

[ozwinner]

Whats a feet?

[Bob Willson]

Not a feet ... afoot. As in "The game is afoot." I'm not really sure what that actually means. Does it mean perhaps that there is also a game called ahand?

[macca2]

Working it by longhand using 1950 2nd year high school memory each side will be 4"6".

I think

Macca:confused:

[Robert WA]

What is "the inscribed diameter"?????

If you convert all the measurements to kilofurlongs and cubits it will be much simpler to calculate.

[silentC]

A chain, a rod and three bargepoles....

[fxst]

Jeez this ones easy mate 3.5 cubits.:D

[Ralph Jones]

Greetings Friends,
I forgot that you chaps are more used to working in the metric system and as already noted you don't even know what a foot is.

An inscribed diameter is the measurement from wall to wall inside measurement as compared to the circumscribed measurement which is the out side points of a polygon.

Also as stated one inch is equals to 25 mm, so a foot would be 300mm and so on. I have always been taught in feet and inches and never worked much with metric but, I will try to explain to you the method of using feet and inches.

Now for the quiz, Figuring the inscribed measurement is a technical thing that usually is better figured by trigonometry and the scientific portion of a calculator with the capabilities of sin, cos, and tangent. I choose not to use them as I have a framing square manual that already has them laid out for me using a 12" diameter or one foot.

Now for an inscribed diameter of one foot, for an 8 sided structure is 4.9705", so all you need to do is multiply that by the diameter of 12' = 59.646" /12 = 4.9705' or rounded off to 5'.

You will note that you already had the answer right from the start on a 12' diameter as all you had to do was change the figure from " to ' and round it off.

Thank you for your support.

Respectfully, :)

[Robert WA]

"Circumcised measurement"????
I am too scared to ask.

[Sturdee]

Originally posted by Robert WA
"Circumcised measurement"????
I am too scared to ask.

Just as well that there is an ocean between Ralph and us. :D :D

Peter.

[bob w]

Sh*t fellas this is easy.
It's 1/8th of the round bit of a 12' circle.
Don't know why you make everything so hard!
Good luck
Bob

[AlexS]

Think metric...it's a dozen times easier.

[DavidG]

Thats gross.

[bitingmidge]

"Circumcised measurement"????

Didn't Bass and Flinders circumcise Australia with an 18 foot cutter?


P

[JackoH]

Ralphy. Ain't you glad you asked ?..http://www.ubeaut.biz/offwall.gif