View Full Version : Maths problem 9999
Wongo
5th March 2008, 10:35 PM
Use exactly four 9s and any number of arithmathic or higher level math operations to make numbers from 1 to 20.
Example
1=(9+9)/(9+9)
7=(9+9+sqrt9)/(sqrt9)
Here is a cracker from a few years back. Have fun.:D
watson
5th March 2008, 10:53 PM
Can't.......got a headache Wongo.......and I will have until you post the answer
ss_11000
6th March 2008, 01:38 AM
1 = (9+9) / (9+9) ..................................18 / 18 = 1
2 = (sqrt9 * sqrt9 + 9) / 9 ................................18/9 = 2
3 = (9+9+9) / 9 .................................27 / 9 = 3
4 = (sqrt9 * 9 +9) /9.....................36/9 = 4
5
6 = sqrt9 ((9+9) / 9)............................ 3 * 18/9 = 6
7 =(9+9+sqrt9)/(sqrt9)............................ 21/3 = 7
8 = (9 squared - 9) / sqrt9 * sqrt9...........................72/9 = 8
9 = (((9*9) / sqrt9) /sqrt9)..........................81 / 3 / 3 = 27/3 = 9
10 =( sqrt9 * 9 + sqrt9) /sqrt9.............................30 / 3 = 10
11 = (9 squared + 9 + 9 ) / 9.....................99/9 = 11
12 = sqrt9 + sqrt9 +sqrt9 +sqrt9...................3+3+3+3 = 12
13
14 = (9 squared + sqrt9) / (sqrt9 + sqrt9 )......................(81 + 3) / 6 =
15 = sqrt 9 * 9 - sqrt 9 - 9...................3*9 -12 = 15
16
17
18 = sqrt 9 * sqrt9 + sqrt9 *sqrt9...................9+9 = 18
19
20
i'll do the rest later:rolleyes::2tsup:. its to late to think lol:cool:
ss_11000
6th March 2008, 02:00 AM
1 = (9+9) / (9+9) ..................................18 / 18 = 1
2 = (sqrt9 * sqrt9 + 9) / 9 ................................18/9 = 2
3 = (9+9+9) / 9 .................................27 / 9 = 3
4 = (sqrt9 * 9 +9) /9.....................36/9 = 4
5 = (9+sqrt9+sqrt9) / sqrt9.................15/3 = 5
6 = sqrt9 ((9+9) / 9)............................ 3 * 18/9 = 6
7 =(9+9+sqrt9)/(sqrt9)............................ 21/3 = 7
8 = (9 squared - 9) / sqrt9 * sqrt9...........................72/9 = 8
9 = (((9*9) / sqrt9) /sqrt9)..........................81 / 3 / 3 = 27/3 = 9
10 =( sqrt9 * 9 + sqrt9) /sqrt9.............................30 / 3 = 10
11 = (9 squared + 9 + 9 ) / 9.....................99/9 = 11
12 = sqrt9 + sqrt9 +sqrt9 +sqrt9...................3+3+3+3 = 12
13 = (((Sqrt9 + sqrt 9) squared) +sqrt9) / sqrt9 ...........3+3 sqrd +3 / 3 = 39/3 = 13
14 = (9 squared + sqrt9) / (sqrt9 + sqrt9 )......................(81 + 3) / 6 =
15 = sqrt 9 * 9 - sqrt 9 - 9...................3*9 -12 = 15
16
17 (9+9) - (9/9)......1..........................18-1 = 17
18 = sqrt 9 * sqrt9 + sqrt9 *sqrt9...................9+9 = 18
19
20 =
i'll do the rest later:rolleyes::2tsup:. its to late to think lol:cool:.
geez, some of them ^^^ are overly complicated.
eg. 2
9/9 + 9/9 = 1+1 = 2
no wonder my head hurts lol:duh:
Wongo
6th March 2008, 09:17 AM
The "9 squared" bit is a bit dodgy.
What's next 9 thirded, 9 tripled or 9 minus five times four ?? :D
Pat
6th March 2008, 09:24 AM
Wongo, please do not peddle this #$%^& as it will give everyone a doody of a headache (Except Sheddie):q
Wongo
6th March 2008, 09:25 AM
It's fun. Stirlo is enjoying it.:U
ss_11000
6th March 2008, 01:05 PM
The "9 squared" bit is a bit dodgy.
What's next 9 thirded, 9 tripled or 9 minus five times four ?? :D
why???
it works:cool: and thats all that matters:D
Gingermick
6th March 2008, 01:38 PM
9-9+9²/9=9
Wongo
6th March 2008, 01:43 PM
why???
it works:cool: and thats all that matters:D
No it doesn't grasshopper. 9 squared is not the math operation we want here. It is 9 to the power of 2 (we don't want the 2 here) unless you can find a symbol that does that (for example square root):cool:
See.:D
Wax on wax off....:p
Wongo
6th March 2008, 01:44 PM
9-9+9²/9=9
Only 9s and symbols sir.
Ashore
6th March 2008, 02:34 PM
1 = (9+9) / (9+9) ..................................18 / 18 = 1
2 = (sqrt9 * sqrt9 + 9) / 9 ................................18/9 = 2
3 = (9+9+9) / 9 .................................27 / 9 = 3
4 = (sqrt9 * 9 +9) /9.....................36/9 = 4
5
6 = sqrt9 ((9+9) / 9)............................ 3 * 18/9 = 6
7 =(9+9+sqrt9)/(sqrt9)............................ 21/3 = 7 9 - (9 + 9 )/9 = 7
8 = (9 squared - 9) / sqrt9 * sqrt9...........................72/9 = 8 [( 9 x 9 )-9 ]/9 = 8
9 = (((9*9) / sqrt9) /sqrt9)..........................81 / 3 / 3 = 27/3 = 9
10 =( sqrt9 * 9 + sqrt9) /sqrt9.............................30 / 3 = 10 [( 9 x 9 ) + 9 ] / 9 = 10
11 = (9 squared + 9 + 9 ) / 9.....................99/9 = 11 9 + (9 + 9 ) / 9 = 11
12 = sqrt9 + sqrt9 +sqrt9 +sqrt9...................3+3+3+3 = 12
13
14 = (9 squared + sqrt9) / (sqrt9 + sqrt9 )......................(81 + 3) / 6 =
15 = sqrt 9 * 9 - sqrt 9 - 9...................3*9 -12 = 15
16
17 (9 + 9 ) - ( 9/9 ) = 17
18 = sqrt 9 * sqrt9 + sqrt9 *sqrt9...................9+9 = 18 [(9+9) /9] x 9 = 18
19 ( 9 + 9 ) + (9 / 9 ) = 19
20
i'll do the rest later:rolleyes::2tsup:. its to late to think lol:cool:
Some limited help :rolleyes:
Ron Dunn
6th March 2008, 02:43 PM
Anywhere you used 9-squared, just replace it with (9*9).
ss_11000
6th March 2008, 03:08 PM
Anywhere you used 9-squared, just replace it with (9*9).
but then i might use two many 9's.:cool:
i see your point now scott...does seem like cheating lol:D
9 + (9 + 9 ) / 9 = 11...ashore, this one doesnt work:?:cool:
ss_11000
6th March 2008, 03:11 PM
1 = (9+9) / (9+9) ..................................18 / 18 = 1
2 = (sqrt9 * sqrt9 + 9) / 9 ................................18/9 = 2
3 = (9+9+9) / 9 .................................27 / 9 = 3
4 = (sqrt9 * 9 +9) /9.....................36/9 = 4
5 = (9+sqrt9+sqrt9) / sqrt9.................15/3 = 5
6 = sqrt9 ((9+9) / 9)............................ 3 * 18/9 = 6
7 =(9+9+sqrt9)/(sqrt9)............................ 21/3 = 7
8 = [( 9 x 9 )-9 ]/9 = 8
9 = (((9*9) / sqrt9) /sqrt9)..........................81 / 3 / 3 = 27/3 = 9
10 =( sqrt9 * 9 + sqrt9) /sqrt9.............................30 / 3 = 10
11 = 9 + sqrt9 - 9/9 9 + (9 + 9 ) / 9 = 11
12 = sqrt9 + sqrt9 +sqrt9 +sqrt9...................3+3+3+3 = 12
13 = 9 + sqrt9 + 9/9
14 =
15 = sqrt 9 * 9 - sqrt 9 - 9...................3*9 -12 = 15
16
17 (9+9) - (9/9)................................18-1 = 17
18 = sqrt 9 * sqrt9 + sqrt9 *sqrt9...................9+9 = 18
19 ( 9 + 9 ) + (9 / 9 ) = 19
20 =
i'll do the rest later:rolleyes::2tsup:. its to late to think lol:cool:.
3 left
Wongo
6th March 2008, 03:16 PM
9 + (9 + 9 ) / 9 = 11...ashore, this one doesnt work:?:cool:
Why not?
Wongo
6th March 2008, 03:18 PM
Only 4 left guys.
13
14
16
20
ss_11000
6th March 2008, 03:24 PM
Why not?
9 + (9 + 9 ) / 9 = 11...
9 + 18 / 9 = 27/9 = 3
:?:?:?
Wongo
6th March 2008, 03:27 PM
9 + (9 + 9 ) / 9 = 11
9 + (18) / 9
9 + 2 = 11
What is rule #1 in Arithmetic?
Oh dear...:D
ss_11000
6th March 2008, 03:29 PM
9 + (9 + 9 ) / 9 = 11
9 + (18) / 9
9 + 2 = 11
Oh dear...:D
:duh::duh::duh:
forget i sed anything would ya:-:doh:
Greg Ward
6th March 2008, 04:20 PM
A late start but.....
9 + 9/9 + Square root of 9 = 13
Wongo
6th March 2008, 04:32 PM
Only 3 left
14
16
20
....hard aren't they??
Ashore
6th March 2008, 08:33 PM
( 9 + 6 ) - 9/9 = 14
( 9 + 6 ) + 9/9 = 16
( 9 + 9 ) + ( 6/sqrt9 ) = 20
you sod wongo I was trying to do my tax today this was the last thing I needed , had to take one of the grandsons for a walk after tea to look at it from out of the box , I take it upside down 9's are ok :U
ss_11000
6th March 2008, 08:54 PM
hey wongy:cool:
is this allowed 14 = 99/9 +sqrt9 ??????????????
there's four nines:D
Ashore
6th March 2008, 09:01 PM
If upside down 9's arn't then that is
Good one Stirlo :2tsup:
as would be 99/9 + 9 = 20
still leaves 16 though
Greg Ward
7th March 2008, 07:24 AM
If 99 isn't allowed:
(((Square root 9)! x 9) + (Square root 9)!)/Square root 9 = 20
greg
Greg Ward
7th March 2008, 07:33 AM
9 + (square root 9)! + 9/9 = 16
greg
Wongo
7th March 2008, 09:04 AM
Sorry children
No 99, no 6. Just 9.
Greg, I like your approach.:2tsup: It is different from my way but I like it. You got game mate. 16 works but not 20.
2 left...
14
20
Greg Ward
7th March 2008, 09:11 AM
let's see.
(square root9)! = 6
6 x 9 =54
54 + (square root 9)! = 60
60/ (Square root 9) = 20
Why doesn't this work?
Greg
Greg Ward
7th March 2008, 09:13 AM
9 + (Square root 9)! - 9/9 = 14
Now Wongo..... I've showed you mine, you've got to show yours.....
Greg
Wongo
7th March 2008, 09:19 AM
Sorry Greg, there were too many (((((( and I read it wrong. 20 works now. :2tsup: My bad.:D
Well done
:fireworks:
Greg Ward
7th March 2008, 09:22 AM
Still want to see your method Wongo, to see what you do here.
Thanks
Greg
Wongo
7th March 2008, 09:26 AM
http://www.woodworkforums.ubeaut.com.au/attachment.php?attachmentid=1288&d=1074572624
ss_11000
7th March 2008, 04:16 PM
good work wongy, greg and russel:2tsup:
Ivan in Oz
7th March 2008, 06:54 PM
9 + (square root 9)! + 9/9 = 16
greg
Please be Gentle with me......
OK!
9 = 9,
and
9/9 = 1,
but WTH!!!:?
(Sq Rt 9)!.......Isn't that 3, NOT 6????? Please Explain
Wongo
7th March 2008, 10:32 PM
n! = n * n-1 * n-2 * n-3 * ....* 1
for example
4! = 4 * 3 * 2 * 1
1! = 1
By definition 0! = 1
9 + (square root 9)! + 9/9
= 9 + 3! + 9/9
= 9 + 6 + 1
=16
Frank&Earnest
8th March 2008, 12:20 PM
Interesting. I can do 21 and 22, can you?:D
Frank&Earnest
8th March 2008, 10:02 PM
No takers? Actually, once you have got the idea it becomes almost mundane up to 64. 65 is a bit challenging and now I am stuck at 67. Think I will go back to woodworking. Anybody out there more determined than I am? :oo:
Wongo
8th March 2008, 10:24 PM
I can do 6561 can you?:rolleyes:
:D
Frank&Earnest
9th March 2008, 11:56 AM
I can do 6561 can you?:rolleyes:
:D
Wow, that was tough! It took me all night, but I finally cracked it!:U
I still haven't cracked 67 though... does anybody know whether it is even possible?
ss_11000
9th March 2008, 10:21 PM
n! = n * n-1 * n-2 * n-3 * ....* 1
for example
4! = 4 * 3 * 2 * 1
1! = 1
By definition 0! = 1
9 + (square root 9)! + 9/9
= 9 + 3! + 9/9
= 9 + 6 + 1
=16
thanx wongo, was wondering what that meant:2tsup:.
now i will know before every one else when we learn that later this year:D
Groggy
9th March 2008, 10:34 PM
Sorry Greg, there were too many (((((( Starting to look like LISP code :cool:
Wongo
10th March 2008, 09:49 AM
I still haven't cracked 67 though... does anybody know whether it is even possible?
I tried it but couldn't do it. Sorry.
Frank&Earnest
10th March 2008, 11:58 AM
Thanks Wongo, once worked out that each 9 can be modified by symbols to make 1, 3, 6 and 9 I thought that maybe all integers could be made up with these four numbers, or something silly like that, but it appears that this hypothesis was too far fetched.:- So, again, back to woodworking!:U
Koala-Man
10th March 2008, 04:25 PM
The "9 squared" bit is a bit dodgy.
What's next 9 thirded, 9 tripled or 9 minus five times four ?? :D
I agree. Squared is the power of 2. That's got a 2 in it.
Ivan in Oz
10th March 2008, 06:59 PM
And Square Root is the Power to HALF......One on TWO:?:oo:
Ivan in Oz
10th March 2008, 07:01 PM
Sq Root is the Power to 0.5.....Same thing
Frank&Earnest
10th March 2008, 08:36 PM
The first post said "Use exactly four 9s and any number of arithmethic or higher level math operations." If the operation can be expressed by symbols without numeric terms it seems to be allowed: log (x), !, etc.
The issue here is whether to allow the symbol for square root because by convention the exponent 2 is omitted, while cubic root, for example, is not allowed because the exponent 3 must be written. The 9th root of nine, however, would have to be allowed, unquestionably, but it uses two of the four 9s allowed and is useless anyway.
We need to ask the third umpire.:D
Wongo
10th March 2008, 10:13 PM
:clap3: He got game.
Wongo
11th March 2008, 09:04 AM
I have a way to do it but I am not going to.
Consider
ln e = 1,
e/e = 1,
ln pi / ln pi = 1
pi / pi = 1
We can have number 1 without using any 9s. :2tsup:
But I won’t use it because it defects the purpose of this thread.
It is a bit like the stuff lawyers do. Legitimate but very very dodgy. :D
Wongo
11th March 2008, 09:56 AM
Here is another one
cos(pi) = -1
cos(pi) * cos(pi) = 1
:D
Frank&Earnest
11th March 2008, 12:37 PM
Legitimate but very very dodgy. :D
I beg to disagree.:) It is not a legitimate way because the "operation" is not performed on the four nines, it is performed on other numeric entities, albeit represented by symbols (pi, e, etc.). Have you found how to legitimately get 1 from only one 9?
Wongo
11th March 2008, 12:48 PM
Have you found how to legitimately get 1 from only one 9?
No bro.
I have been trying to do exactly that. If I could crack that I could crack 67. No luck so far.:doh:
Frank&Earnest
11th March 2008, 01:30 PM
infinite root of 9
Wongo
11th March 2008, 01:38 PM
Infinite root of 9 doesn't make it 1.
I think the real solution does exist though. The truth is out there.
zelk
11th March 2008, 01:38 PM
infinite root of 9
Almost.
Zelk
Frank&Earnest
11th March 2008, 02:04 PM
Infinite root of 9 doesn't make it 1.
yes it does... you could write it as lim (x->infinite) of x root of 9, if you want to be that way...:D
Wongo
11th March 2008, 02:09 PM
limit is an approximation.:cool:
What is 9 divided by infinity then? Don't tell me it is 0.
:D
Frank&Earnest
11th March 2008, 02:59 PM
I guess you are one of those who still refuse to accept that 0.99999... recurrent is =1, then. You are fighting a rearguard battle, but if that's what lifts your boat...:p I'm not a good enough mathematician to follow you down that path.
Just to amuse me: assuming that you could get 1 from one 9, how do you get 67? It still baffles me.
Wongo
11th March 2008, 03:28 PM
Hang on mate!!
0.99999... is not 1. Why is it so hard to understand?
Just to amuse me: assuming that you could get 1 from one 9, how do you get 67? It still baffles me.
I have more than 1 way to do it but it is pointless so I won't show you. That will keep you thinking.... :U
Wongo
11th March 2008, 06:08 PM
Anyone wants to explain it? :D
http://www.woodworkforums.com/attachment.php?attachmentid=68999&stc=1&d=1205219254
ss_11000
11th March 2008, 06:42 PM
i'll take your word for it:cool:
Frank&Earnest
11th March 2008, 07:00 PM
Brilliant! :2tsup:Still illegal IMHO, though, for the same reason as before: the operation is not performed on the nines, in this case the nines only identify a subset of an unlimited, and therefore infinite, set of functions. If that were allowed, any and all numbers can be produced.
If, however, you have a solution that accepts the way I suggested of producing 1, I would still be keen to see it. We would then let the professors fight over it. (If you can still find any who champions your cause...:D) I have to admit that I do not have a great opinion of Adelaide academics, though, you might end up being right...:C
Wongo
11th March 2008, 11:05 PM
Well it is as illegal as the factorial. Both are mathematics notations not operators. We accepted factorial so we should accept summation too.
I think it is ok. Trust me.:cool:
I will let you know the other 2 ways when I remember them.:D
Wongo
11th March 2008, 11:08 PM
i'll take your word for it:cool:
C’mon grasshopper. That is not the right attitude. :U
You need to work it out.
Frank&Earnest
12th March 2008, 12:59 PM
Well it is as illegal as the factorial. Both are mathematics notations not operators. We accepted factorial so we should accept summation too.
I think it is ok. Trust me.:cool:
I will let you know the other 2 ways when I remember them.:D
Hmmm.... As I always say to my daughter, never trust anybody who says "trust me"...:p
I still think that not being anally retentive about notations v. operators is OK (it reinforces my acceptance of lim x) , but does not change my point that you are working on infinite functions, not on the four nines, which denies the intention.
Wongo
12th March 2008, 01:12 PM
No worries mate. Take away both the ! notation and E notation. (sorry Greg, your solutions for 1 to 20 were wrong :D)
Re the acceptance of lim x, mate let me say it one more time 0.99999... is not 1.:cool: It's not even close.
:D
Frank&Earnest
12th March 2008, 01:23 PM
Re the acceptance of lim x, mate let me say it one more time 0.99999... is not 1.:cool: It's not even close.
:D
Well, tell that to my son's calculus professor... I'm too old for this... :C
You wouldn't still be stuck in Euclidean space, perchance?
Wongo
12th March 2008, 02:13 PM
It doesn’t matter if it is for a professor in calculus. 0.999999… is not equal to 1. It is a fact. You can round it up to 1 but it is not 1.
ss_11000
12th March 2008, 03:21 PM
C’mon grasshopper. That is not the right attitude. :U
You need to work it out.
yeah sure.:rolleyes:
i'll let you know in a couple of months:2tsup:
Frank&Earnest
12th March 2008, 08:52 PM
It doesn’t matter if it is for a professor in calculus. 0.999999… is not equal to 1. It is a fact. You can round it up to 1 but it is not 1.
Do you accept that for any two numbers a and b there is an average number in between c = (a+b)/2?
Wongo
13th March 2008, 09:01 AM
No I don't
Frank&Earnest
13th March 2008, 12:13 PM
f
ss_11000
28th December 2008, 12:21 AM
Anyone wants to explain it? :D
http://www.woodworkforums.com/attachment.php?attachmentid=68999&stc=1&d=1205219254
Quote:
Originally Posted by Wongo http://image-mirror.cyanide.com.au/woodworkforums/images/button2/viewpost.gif (http://www.woodworkforums.com/showthread.php?p=699129#post699129)
C’mon grasshopper. That is not the right attitude. :U
You need to work it out.
yeah sure.:rolleyes:
i'll let you know in a couple of months:2tsup:
__________________
S T I R L O :lbs:
gday wongo, i just came across this thread again.
dunno if i'm right but does that (^^^) mean that the sum of the 3rd through to 6th terms of that series is 68, and minus the 1 it equals 67?:?
btw wongo, i got a headband that looks just like your avatar :D
Wongo
28th December 2008, 12:07 PM
dunno if i'm right but does that (^^^) mean that the sum of the 3rd through to 6th terms of that series is 68, and minus the 1 it equals 67?:?
Correct
echnidna
28th December 2008, 05:06 PM
so how much sawdust is that in cubic metres?
ss_11000
28th December 2008, 06:50 PM
sweet. :cool:
we learnt that stuff last term (sequences and series).
Wongo
29th December 2008, 12:15 PM
so how much sawdust is that in cubic metres?
1 cubic metre. :2tsup:
:U
ajw
29th December 2008, 06:46 PM
Or would that be 9/9 + (9-9) cubic metres?:)
Afro Boy
22nd March 2009, 06:44 PM
Sorry to dig up an old thread but I found this clock that some of you math-heads might enjoy.
http://geekswithblogs.net/ram/archive/2008/01/04/118249.aspx
Wongo
22nd March 2009, 10:31 PM
Thats 9 out of 9. :D
masoth
22nd March 2009, 10:55 PM
Fascinating clock, Afro Boy.
soth
Skew ChiDAMN!!
22nd March 2009, 11:31 PM
Thats 9 out of 9. :D
Sorry, I'll only rate it 8/9.
Look at the formula for the number 7. :~ It's out by 0.0111...
Afro Boy
23rd March 2009, 10:39 AM
Thats 9 out of 9. :D
<groan> :;
Wongo
23rd March 2009, 10:51 AM
Sorry, I'll only rate it 8/9.
Look at the formula for the number 7. :~ It's out by 0.0111...
Stupid isn't it? I suppose it is good enough for primary school students.:rolleyes:
Skew ChiDAMN!!
23rd March 2009, 04:07 PM
Then again, it's only an analogue clock.
Who needs accuracy for "it's a quarter to nine?"
Wongo
23rd March 2009, 10:17 PM
Trouble is these people don't have a clue. They are teaching people the wrong stuff.:~ To make it worse, 7 can easily be written as sqrt(9)! + (9/9).:doh:
adamtas
28th March 2009, 01:46 PM
The first one I thought of was 99 - (9*9) = 99 - 81 = 18.
Then I saw there were 6 pages of answers. Back to the gardening....
czk
8th April 2009, 02:38 PM
It doesn’t matter if it is for a professor in calculus. 0.999999… is not equal to 1. It is a fact. You can round it up to 1 but it is not 1.
but why not just do this, ceiling is a legitimate operator
Wongo
8th April 2009, 09:47 PM
Sorry, I am not with you. :?
Skew ChiDAMN!!
9th April 2009, 03:42 AM
http://en.wikipedia.org/wiki/Ceiling_function
'Tis a new one on me, but that's nothing new. :rolleyes:
czk
9th April 2009, 10:51 AM
the ceiling of x is the smallest integer greater than or equal to x.
floor is probably more common but both are perfectly valid functions
rosewood
9th April 2009, 03:50 PM
.
3 left
It,s things like this that make me think i should keep life simple and clean the shed more often.